Minimaalne ajaxi näide
Allikas: Lambda
<html>
<head>
<script>
var request;
function myupdatefun() {
var response;
alert("myupdatefun called with"+request.readyState)
if (request.readyState == 4) {
alert("Server is done, request.readyState == 4!");
if (request.status == 200) {
alert("Server sent data ok,request.status == 200!");
response = request.responseText
alert("response is: "+response)
document.getElementById('sisu2').innerHTML=response;
} else if (request.status == 404)
alert("Request URL does not exist");
else
alert("Error: status code is " + request.status);
}
}
function ajaxcall() {
var url;
request = new XMLHttpRequest();
url = "http://dijkstra.cs.ttu.ee/~tammet/cgi-bin/otsi.py?salvestaja=tanel&table=t1"
request.open("GET", url, true);
request.onreadystatechange = myupdatefun;
request.send(null);
}
</script>
<body>
Tere kah!
<form>
<input type="button" value="Proovi!" onclick="ajaxcall()">
</form>
<div id="sisu2"></div>
</body>
